Розділ 2. РОЗКЛАДАННЯ МНОГОЧЛЕНІВ » 439

Подай вираз у вигляді добутку. a) 2x + 2y + ax + ay = (2x + 2y) + (ax + ay) = 2(x + y) + a(x + y) = (x + y)(2 + a); б) xa – xb + ca – cb = (xa – xb) + (ca – cb) = x(a – b) + c(a – b) = (a – b)(x + c); в) 2a – 2b + ca – cb = (2a – 2b) + (ca – cb) = 2(a – b) + c(a – b) = (a – b)(2 + c); г) mx + ny + mx + my = (nx + ny) + (mx + my) = n(x + y) + m(x + y) = (x + y)(n + m); ґ) ax – bx – ay + by = (ax – bx) – (ay – by) = x(a – b) – y(a – b) = (a – b)(x – y); д) mx + my – cx – cy = (mx + my) – (cx + cy) = m(x + y) – c(x + y) = (x + y)(m – c) е) 2x + 2y – ax – ay = (2x + 2y) – (ax + ay) = 2(x + y) – a(x + y) = (x + y)(2 – a); є) ap – ak – p + k = (ap – ak) – (p – k) = a(p – k) – (p – k) = (p – k)(a – 1);