Вправи для повторення розділу 3 » 37 (4)

4) (4x^2- 11x-3)/(〖-3x〗^2+ 10x-3). 4x2 – 11x – 3 = 0; D = (–11)2 – 4 • 4 • (–3) = 169; x1 = (11+13)/8 = 3; x2 = (11-13)/8 = –1/4. –3x2 + 10x – 3 = 0; D = 102 – 4 • (–3) • (–3) = 64; x1 = (-10+8)/(-6) = 1/3; x2 = (-10-8)/(-6) = 3. (4x^2- 11x-3)/(-3x^2+ 10x-3) = (4(x-3)(x+ 1/4))/(-3(x-3)( x- 1/3)) = (4x+1)/(1-3x).