Задачі підвищеної складностістр » 3 (4)

4/(x+1/(y+1/z ) ) : 1/(x+1/y) – 4/(y(xyz+ x+ z)) = 4. 1. 4/(x+ 1/(y+1/z)) = 4/(x+ 1/((yz+1)/z)) = 4/(x+ z/(yz+1)) = 4/((xyz+ x+ z)/(yz+1)) = (4(yz+1))/(xyz+ x+ z); 2. (4(yz+1))/(xyz+ x+ z) : 1/((xy+1)/y) = (4(yz+1))/(xyz+ x+ z) : y/(xy+1) = (4(yz+1)(xy+1))/(y(xyz+ x+ z)); 3. (4(yz+1)(xy+1))/(y(xyz+ x+ z)) – 4/(y(xyz+ x+ z)) = 4 • (xy^2 z+ yz+ xy+1-1)/(y(xyz+ x+ z)) = 4 • (y(xyz+ x+ z))/(y(xyz+ x+ z)) = 4.