Вправи 888 - 1000 » 997 (ґ)

ґ) x|x| – 4x + 3 = 0; 1) x < 0; –x2 – 4x + 3 = 0; D = (4)2 – 4 • (–1) • 3 = 16 + 12 = 28; x1 = (4- √28)/(-2) – (4-2√7)/(-2) = –2 + √7 > 0 – не задовольняє умову; х2 = (4+ √28)/(-2) = (4+2√7)/(-2) – –2 – √7; 2) x ≥ 0; x2 – 4 + 3 = 0; D = (–4)2 – 4 • 1 • 3 = 16 – 12 = 4 = 22. x1 = (4-2)/2 = 2/2 = 1; x2 = (4+2)/2 = 6/2 = 3. Відповідь: –2 – √7; 1; 3.