Вправи 501 - 595 » 529





Знайдіть значення виразу: 1) (3√2 + 1)( √8 – 2) = 3√16 – 6√2 + √8 – 2 = 3 • 4 – 6√2 + 2√2 – 2 = 12 – 6√2 + 2√2 – 2 = 10 – 4√2; 2) (3 – 2√7)2 + (3 + 2√7)2 = 9 – 12√7 + 28 + 9 + 12√7 + 28 = 74; 3) (10 – 4√6)(2 + √6)2 = (10 – 4√6)(4 + 4√6 + 6) = (10 – 4√6)(10 + 4√6) = 102 –(4√6)2 = 100 – 96 = 4; 4) (√(9-4√2) + √(9+4√2) )2 = (√(9-4√2) )2 + 2√((9-4√2)(9+4√2))2 + (√(9+4√2) )2 = 9 – 4√2 + 2√(9^2- (4√2 )^2 ) + 9 + 4√2 = 18 + 2√(81-32) = 18 + 2√49 = 18 • 2 • 7 = 18 + 14 = 32.





Вправи 501 - 595