РОЗДІЛ 2. Раціональні вирази - Вправи 50 - 200 » 168 (2)
2) y = (3x+4)/(5x-10) – (x+4)/(3x-6) = 〖3x+4〗^(\3)/(5(x-2)) – 〖x+4〗^(\5)/(3(x-2)) = (9x+12-5x-20)/(15(x-2)) = (4x-8)/(15(x-2)) = 4/15; ОДЗ: x – 2 ≠ 0; x ≠ 0; y = 4/15.
2) y = (3x+4)/(5x-10) – (x+4)/(3x-6) = 〖3x+4〗^(\3)/(5(x-2)) – 〖x+4〗^(\5)/(3(x-2)) = (9x+12-5x-20)/(15(x-2)) = (4x-8)/(15(x-2)) = 4/15; ОДЗ: x – 2 ≠ 0; x ≠ 0; y = 4/15.