Відповіді §.15 - §.16 » §.16 (1)

За заданою формулою n-го члена послідовності: 1. xn = n/4 x1 = 1/4 x2 = 2/4 = 1/2 x3 = 3/4 2. Cn = 7 – 2n. C1 = 7 – 2 • 1 = 5. C2 = 7 – 2 • 2 = 3. C4 = 7 – 2 • 4 = –1. 3. an = 12/n + 3 a1 = 12/1 + 3 = 15 a2 = 12/2 + 3 = 9 a6 = 12/6 + 3 = 5 ap = 12/p + 3 ak+1 = 12/(k+1) + 3. 4. yn = 3n2 – 14 y1 = 3 • 12 – 14 = –11 y2 = 3 • 22 – 14 = –2 y12 = 3 • 122 – 14 = 418 yk = 3k2 – 14 ym–3 = 3(m – 3)2 – 14 = 3m2 – 18m + 27 – 14 = 3m2 – 18m + 13.