Вправи 1001 - 1100 » 1071

Розкрийте дужки: 1) 3/7b(14t – 7/9y + 21/3c) = – (3 • 14)/7bt – (3 • 7)/(7 • 9)by + (3 • 7)/(7 • 3)bc = –6bt – 1/3by + bc; 2) –1,2xy (5m – 6c + 1/6t – 5/6) = – (6 • 5)/5xym + (6 • 6)/5xyc – 6/(5 • 6)xyt + (6 • 5)/(5 • 6)xyz – 6xym + 71/5xyt ∙ xy; 3) 0,3nm(1,5 – 6bс + 7b – 10с) = 0,45mn – 1,8bсmn + 2,1 bmn – Зсmn.