Вправи 301 - 400 » 359 (5-6)

5) 15–6 = x • (1/9)3; (5 • 3)–6 = x • (1/3^1 )3 5–6 • 3–6 = x • 3–6 |: 3–6 x = 5–6. 6) (0,6–5)3 = (1/5^(-3) )5 • x; (6/10)–15 = 1/5^(-15) • x; (3/15)–15 = 1/5^(-15) • x; 3^(-15)/5^(-15) = x/5^(-15) ; x = 3–15.