Завдання 1201 - 1300 » 1265

Розкрий дужки: 1) 3(а + 1) = 3 · а + 3 · 1 = 3m + 3; 2) 3(x – 4) = 3 · x – 3 · 4 = 3x – 12; 3) –5(2х + 1) = –5 · 2х + (–5) · 1 = –10х – 5; 4) (–1,6х + 2) · (–5) = –1,6х · (–5) + 2 · (–5) = 8х – 10; 5) (–2х – у) · 3 = –2х · 3 – у · 3 = –6х – 3у; 6) –7 · (х – 2) = –7 · х – 7 · (–2) = –7х + 14; 7) (а – b) · (–3) = –3a – b · (–3) = –3a + 3b; 8) (–4a + 5b) · 2 = –4a · 2 + 5b · 2 = –8a + 10b.