Завдання 301 - 400 » 376

Розкрий дужки: 1) 7(3/7 + 4/7а) = (7 ∙ 3)/7 + (7 ∙ 4)/7а = 3 + 4а; 2) 1/2(3/4 – 6/7b) = (1 ∙ 3)/(2 ∙ 4) – (1 ∙ 6)/(2 ∙ 7)b = 3/8 – 3/7b; 3) 11/6 (2x – 5/14y + 11/2) = (7 ∙ 2)/6x – (7 ∙ 5)/(6 ∙ 14)y + (7 ∙ 3)/(6 ∙ 2) = 21/3x – 5/12y + 13/4.

Завдання 301 - 400