Вправи: 419

419. Винеси за дужки спільний множник.

a) (5x + 10)² = (5(x + 2))² = 25(x + 2)²;

б) (3 – 12y)² = (3(1 – 4y))² = 9(1 – 4y)²;

в) (4a – 4b)³ = (4(a – b))³ = 64(a – b)³;

г) (3a + 6c)⁴ = (3(a + 2c))⁴ = 81(a + 2c)⁴;

ґ) (6ab² – 3a²)³ = (3a(2b² – a))³ = 27a³(2b² – a)³;

д) (–6a – 2ab)⁴ = (6a + 2ab)⁴ = (2a(3 + b))⁴ = 16a⁴(3 + b)⁴.