Відповіді АЛГЕБРА: 18.6

18.6

1) g(x) = 2x + 3, x₀ = 1, ∆x = –0,1;

∆g(x) = g(x₀ + ∆x) – g(x₀) = g(0,9) – g(1) = 2 • 0,9 + 3 – (2 • 1 + 3) = 4,8 – 5 = –0,2;

2) g(x) = x² – 5, x₀ = –1 ∆x = –0,2;

∆g = g(–0,8) – g(–1) = (–0,8)² – 5 –((–1)² – 5) = –4,36 + 4 = –0,36.