Відповіді АЛГЕБРА: 17.24

17.24

f(a + b) – f(a);

1) f(x) = 5;

f(a + b) = 5 f(a) = 5;

f(a + b) – f(a) = 5 – 5 = 0.

2) f(x) = x;

f(a + b) – f(a) = a + b – a = b.

3) f(x) = x²

f(a + b) – f(a) = (a + b)² – a² = 2ab + b²

4) f(x) = x³

f(a + b) – f(a) = (a + b)³ – a³ = a³ + 3a²b + 3ab² + b³ – a³ = b³ +

+ 3a²b + 3ab²

5) f(x) = 1x

f(a + b) – f(a) = 1a+b – 1a = a-a-ba(a+b) = –ba(a+b)

6) f(x) = x

f(a + b) – f(a) = a+b – a