Вправи
Вправи: 403 (1-6)
Готова відповідь до завдання 403 (1-6) з ГДЗ Алгебра 8 клас Тарасенкова.
Алгебра, 8 клас · Вправи

Текстова відповідь
403. Спростіть вираз:
1) a2a+b – b2(a + b)–1 = a2a+b – b2a+b = a2- b2a+b = a-b(a+b)a+b = a – b;
2) 1x+y – x(x + y)–2 = 1\x+yx+y – x(x+y)2 = x+y-x(x+y)2 = y(x+y)2;
3) 2m3m+1 – 2m3(1 – m2)–1 = 2m3m+1 – 2m31-m2 = 2m3\1+m1+m – 2m31-m(1+m) = 2m3+ 2m3+ 2m4- 2m31-m(1+m) = 2m41-m2;
4) 4(a – 2)–1 – a2a-2 = 4a-2 – a2a-2 = 4-a2a-2 = 2-a(2+a)a-2 = –a-2(a+2)a-2 = a – 2
5) (x – 5)–1 + x(x – 5)–1 – 6x+5 = 1x-5 + xx-5 –
6) (x + y)–2 – (x – y)–2 = 1\(x-y)2(x+y)2 – 1\(x+y)2(x-y)2 = x2- 2xy+ y2- (x2+ 2xy+ y2) (x+y)2(x-y)2 = x2- 2xy+ y2- x2- 2xy- y2(x+y)2 • (x-y)2 = –4xy(x+y)2(x-y)2 ;
7) (1 + b)–1 – (1 + b)–2 = 1\1+b1+b – 1(1+b)2 = 1+b -1(1+b)2 = b(1+b)2;
8) (m + n)–1 – (m + n)–2 = 1\m+nm+n – 1(m+n)2 = m+n-1(m+n)2;
9) mn(m2 – 1)–1 – (m-1n)–1 = mnm2- 1 – nm-1 = mnm-1m+1 – n\m+1m-1 = mn-mn-nm-1(m+1) = –nm2- 1 = n1-m2;
10) 1 – (1 + x–1)–1 = 1 – 11+ 1x = 1 – 1x+1x = 1\x+1 – xx+1 = x+1-xx+1 = 1x+1;
11) (1 + (1 + a–1)–1)–1 = (1 + (1 + 1a)–1)–1 = (1 + (a+1a)–1)–1 = (1 + aa+1)–1 = (a+1+aa+1)–1 = (2a+1a+1)–1 = a+12a+1;
12) (a – a–1)–2 + (1 – a2)–2 = (a – 1a)–2 + 1(1-a2)2 = (a2- 1a)–2 + 1(1-a2)2 = (aa2- 1)2 + 1(a2- 1)2 = a2(a2- 1)2 + 1(a2- 1)2 = a2+ 1(a2- 1)2.