Вправи: 445

445. Подайте вираз у вигляді дробу:

1) 415m2 • 5m16 = 4 • 5m15m2 • 16 = 112m;

2) t315 • 20tk = 20t315tk = 4t23k;

3) –24m5a2 • 15a8m3 = –24m • 15a5a2 • 8m3 = –9am2;

4) –12x • (–p16x2) = 12xp16x2 = 3p4x;

5) 15m²n • 725m3n = 15m2n • 725m3n = 215m;

6) 7c312a8 • (–8a521c) = –7c3 • 8a512a8 • 21c = –2c29a3.