Відповіді АЛГЕБРА: 17.16

17.16

1) lim x2- x-6x+ 2 = [00] = lim x+2(x-3)x+2 = lim (x – 3) = –5

x→ –2 x→ –2 x→ –2

2) lim x2- 1x2- 5x+4 = [00] = lim = x-1(x+1)x+1(x+4) = limx-3x+4 = [-1-3-1+4] = -23 =

x→ –1 x→ –1 x→ –1

= –23

3) lim x3- 8x-2 = [00] = limx-2(x2+2x+4)x-2 = lim(x² + 2x + 4) =

x→ 2 x→ 2 x→ 2

= [2² + 2 • 2 + 4] = 12.

4) lim 1- x1-x = [00] = lim (1- x)(1+x)1- x = [1 + 1] = 2.

x→ 1 x→ 1