Відповіді АЛГЕБРА: 17.15

17.15

1) lim x-2x2+2x-8 = [00] = lim (x-2)x-2(x+4) = lim 1x+4 = [12+4] = 16

x→2 x→2 x→2

2) lim x2+ 2x-3x2- 1 = lim x-1(x+3)x-1(x+1) = lim x+3x+1 = [1+31+1] = 42 = 2.

x→1 x→1 x→1

3) lim x3+ 1x+1 = [00] = limx+1(x2-x+1)(x+1) = lim(x² – x + 1) = [1 + 1 +

x→ –1 x→ –1 x→ –1

+1] = 3

4) lim 3- x9-x = [00] = lim 3- x(3- x)(3+x) = lim 13+ 3 = [13+ 3] = 16

x→9 x→ 9 x→9