Вправи
Вправи: 543 (1-7)
Готова відповідь до завдання 543 (1-7) з ГДЗ Алгебра 8 клас Тарасенкова.
Алгебра, 8 клас · Вправи
Текстова відповідь
543. Спростіть вираз:
1) 10(10 – 5) = (10)2 – 510 = 10 – 510;
2) 2(2 + 1) = (2)2 + 2 = 2 + 2;
3) (18 + 1)2 = 36 + 2 = 6 + 2;
4) –3(2 + 3) = –6 – (3)2 = –6 – 3;
5) (2 + 2)(2 – 3) = (2)2 – 32 + 22 – 6 = 2 – 2 – 6 = –4 – 2;
6) (5 + 2)(3 – 3) = 15 – 35 + 23 – 6;
7) (3 +1)(3 – 1) = (3)2 – 12 = 3 – 1 = 2;
8) (2 + 3)(22 – 1) = 2(2)2 – 2 + 62 – 3 = 4 + 52 – 3 = 1 + 52;
9) (10 + 3)(10 – 3) = (10)2 – 32 = 10 – 9 = 1;
10) (6 + 4)(6 – 4) = (6)2 – 42 = 6 – 16 = –10;
11) (5 + 6)(5 – 6) = (5)2 – 62 = 5 – 36 = –31;
12) (2 + 3)(2 – 3) = (2)2 – (3)2 = 2 – 3 = –1;
13) (5 + 2)(5 – 2) = (5)2 – (2)2 = 5 – 2 = 3;
14) (13 + 15)(13 – 15) = (13)2 – (15)2 = 13 – 15 = –2;
15) (2 + 1)2 = (2)2 + 22 • 1 + 12 = 2 + 22 + 1 = 3 + 22;
16) (52 – 1)2 = (52)2 – 2 • 52 • 1 + 12 = 50 – 102 + 1 = 51 – 102;
17) (3 + 1)2 = (3)2 + 2 • 3 • 1 + 12 = 3 + 23 + 1 = 4 + 23;
18) (3 + 6)2 = (3)2 + 2 • 3 • 6 + (6)2 = 3 + 218 + 6 = 9 + 218;
19) (10 – 5)2 = (10)2 – 2 • 10 • 5 + (5)2 = 10 – 250 + 5 = 15 – 250
20) (23 + 7)2 = (23)2 + 2 • 23 • 7 + (7)2 = 12 + 421 + 7 = 19 + 421.