Вправи: 166

166. Подайте у вигляді раціонального дробу:

1) x + 1x = x\x1 + 1x = x2+ 1x;

2) 3x + 3x = 3x\x1 + 3x = 3x2+ 3x;

3) 1x2 + 4x = 1x2 + 4x\x21 = 1+4x3x2;

4) 7y – y² = 7y – y2\y1 = 7-y3y;

5) 4-2aa – 2a = 4-2aa – 2a1 = 4-2a-2a2a;

6) b7-b – 9b = b7-b – 9b\7-b1 = b-63b+9b27-b = 9b2- 62b7-b;

7) 5a – 10a22a-1 = 5a1 – 10a22a-1 = 10a2- 5a- 10a22a-1 = -5a2a-1;

8) 2cc-5 – 2c – 1 = 2cc-5 – 2c+1\c-51 = 2c-2c2- 10c+c-5c-5 = -2c2- 7c-5c-5;

9) 1 + -x+x22x-1 – x = -x+x22x-1 + 1-x\2x-11 = -x+x2+ 2x-1- -2x2+ x2x-1 = -x2+ 2x-12x-1 = -(x2- 2x+1)2x-1 = -(x-1)22x-1 = (x-1)21-2x.