Відповіді АЛГЕБРА: 16.32

16.32

sin(2x – π6) = 0 [–5π6; 2π3];

2x – π6 = πn, n є z;

2x = π6 + πn;

x = π12 + πn6, n є z;

n = 0; x = π12

n = 1; x = π12 + π2 = π+6π12 = 7π12

n = –1; x = π\112 – π\62 = -5π12

n = –2; x = π12 – π = π-12π12 = –11π12 є [–5π6; 2π3].